Prove that : sin(90° - θ)sin θ/tan θ - 1 = -sin^2 θ - Sarthaks
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Prove that : sin(90° - θ)sin θ/tan θ - 1 = -sin2 θ
सिद्ध कीजिये की : (sin (90^@-theta)sin theta)/(tan theta)-1=-sin^2 the
Prove that: i. √(1 - sinθ)/(1 + sinθ) = secθ − tanθ ii (sec θ – cos θ) (cot θ + tan θ) tan θ. sec θ - Sarthaks eConnect
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