What is the compressibility factor (Z) for 0.02 mole of a van der Waal

(d) (0.1+(1000xx(0.02)^(2))/(V^(2)))V=20xx0.02 =0.1V^(2)-0.4V+0.4=0 =V^(2)-4V+4=0 implies" "V=2L Z=(PV)/(nRT)=(0.1xx2)/(20xx0.02)=0.5

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What is the compressibility factor (Z) for 0.02 mole of a van der

Solved We showed, for a van der Waals gas, that the

jo 22] What is the compressibility factor (Z) 0.02 mole of a van der Waals' gas pressure of 0.1 atm. Assume the size of gas molecules is negligible.

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Compressibility factor (Z) for a van der Waals real gas at

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al Gases f.a What is the compressibility factor (Z) 0.02 mole of a van der Waals' gas pressure of 0.1 atm. Assume the size of gas molecules is negligible. Given: RT =

ODPOOD B-76.& What is the compressibility factor (Z) 0.02 mole of a van der Waals' gas pressure of 0.1 atm. Assume the size of gas molecules is negligible. Given : RT =

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One way of writing the equation of state for real gases is PV = RT [1+

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Answered: The van der Waals equation of state for…